/*
	Example of passing arrays to functions. 
	John Sterling
	CS1124
	Polytechnic University
*/

#include <iostream>	// cout, endl
using namespace std;

void display(const int x[], int size);
void display2d(const int x[][3], int size);

int main() {

	int arr[] = {2, 3, 5, 8, 13};
	int arr2[] = {2, 4, 8, 16, 32, 64, 128};
	int arr2d[][3] = {{2, 4, 8}, {3, 9, 27}};	// A 2d array is just an array of arrays.

	// To pass an array to a function, just give the name of the array.
	// The array's name is really just the "address" (or location) of 
	// the whole array.  The array, itself, is NOT being copied,
	// only the address of the array.  Even though this looks like pass-by-value,
	// we are NOT making a copy of the array and any changes that the function
	// makes to the array WILL actually change the array that was passed in.
	display(arr, 5);
	display(arr2, 7);
	// Even if the array has more than one dimension we can pass the whole
	// array just by giving the array's name.  Again, what we're really passing
	// is just the address (or location) of the array.
	display2d(arr2d, 2);
}

// This function displays an array.  There is no way in C++ for the function to 
// know how big the array is just by looking at it, so we also have to pass 
// the size of the array.
void display(const int x[], int size) {
	for (int i = 0; i < size; i++)
		cout << x[i] << " ";
	cout << endl;
}

// This functoin is passed a two dimensional array to print.
// It does so by passing each array to the function that displays 
// one-dimensional arrays.
void display2d(const int x[][3], int size) {
	for (int i = 0; i < size; i++)
		display(x[i], 3);
}